If the mass of neutron is assumed to be half of its original value whereas that of electron is assumed to be twice to this original value then atomic mass of C-14 will be (in %)
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14 C 6
number of proton= 6
number of neutron = 8
mass of proton = 6 amu
mass of neutron = 8 amu
total mass = 6 + 8 = 14
now the mass of neutron s halved so,= 8/2 = 4
the mass of proton is doubles = 6 x2
new mass = 6x2 + 4 = 16 amu
% of increase in mass= 16 -14/ 14 x 100
= 14.28 %
number of proton= 6
number of neutron = 8
mass of proton = 6 amu
mass of neutron = 8 amu
total mass = 6 + 8 = 14
now the mass of neutron s halved so,= 8/2 = 4
the mass of proton is doubles = 6 x2
new mass = 6x2 + 4 = 16 amu
% of increase in mass= 16 -14/ 14 x 100
= 14.28 %
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Explanation:
If the mass of neutron is assumed to be half of its original value whereas that of electron is assumed to be twice to this original value then atomic mass of C-14 will be (in %)
Because of the definition of the unified atomic mass unit, each carbon-12 atom has an atomic mass of exactly 12 u, and so a mole of carbon-12 atoms weighs exactly 0.012 kg.
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