If the mass of Neutron is doubled and that of protons is halved,the molecular mass of H2O Containing only H1 and O16 atoms, will
a) increase by 25%
b) decrease by 25%
c) increase by 14%
d) decrease by 14%
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number of proton= 6
number of neutron = 8
mass of proton = 6 amu
mass of neutron = 8 amu
total mass = 6 + 8 = 14
now the mass of neutron s halved so,= 8/2 = 4
the mass of proton is doubles = 6 x2
new mass = 6x2 + 4 = 16 amu
% of increase in mass= 16 -14/ 14 x 100
=14.28%
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