If the mass of the earth is 6 x 10²⁷g and its radius 6400 km, what will be the acceleration due to gravity at a height 64 km above the earth's surface? Given that G = 6.67 x 10^-⁸ CGS unit.
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Answer:
Given that,
Mass of the Earth m
1
=6×10
24
kg
Mass of the Moon m
2
=7.4×10
22
kg
Distance between the Earth and the Moon d=3.84×10
5
km=3.84×10
8
m
Gravitational Constant G=6.7×10
−11
Nm
2
/kg
2
Now, by using Newton’s law of gravitation
F=
r
2
Gm
1
m
2
F=
(3.84×10
8
)
2
6.7×10
−11
×6×10
24
×7.4×10
22
F=
14.8225×10
16
297.48×10
35
F=20.069×10
19
F=20.1×10
19
N
Hence, the gravitational force of attraction is 20.1×10
19
N
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