If the mass of the electron (9×10^-31 kg) is taken as unit of mass, the radius of the first Bohr orbit (0.5×10^-10 m) as unit of length and 500 newtons as unit of force, then the unit of time in the new system would be? 1) 3×10^-22 s 2) 15×10^-12 s 3) 15×10^-20 s 4) 45×10^-20 s
Answers
Answered by
7
Explanation:
Units of Joule are ML
2
T
−2
=kgm
2
s
−2
n
2
=n
1
[
M
2
M
1
][
L
2
L
1
]
2
[
T
2
T
1
]
−2
=1[
10kg
1kg
][
1km
1m
]
2
[
1min
1s
]
−2
=1[
10
1
][
1000
1
]
2
[
60
1
]
−2
=3.6×10
−4
units
Answered by
1
Answer:
Unit of time in new system is 3 x 10⁻²²sec .
Explanation:
Given that :
- Unit of mass = 9 x 10⁻³¹ Kg
- Unit of length = 0.5 x 10⁻¹⁰ m
- Unit of force = 500 N
Solution :
- Since, the dimension of force, F is [M][L][T]⁻²
- This gives,
- 500 = 9 x 10⁻³¹ x 0.5 x 10⁻¹⁰ x [T]⁻²
- [T]²= (9 x 10⁻³¹ x 0.5 x 10⁻¹⁰)/500
- [T]²= 9 x 10⁻⁴⁴ sec
- [T] = 3 x 10⁻²² sec
- Hence, unit of time in new system is 3 x 10⁻²² sec .
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