Question

If the mass ratio of He to N2 in a container is 2 : 1 then the ratio of their moles will be

Answer 1

Answer:

14:1

Explanation:

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Answer 2

Answer : The ratio of their moles will be, 14 : 1

Explanation :

As we are given that the mass ratio of $He$ and $N_2$ in a container is 2 : 1.

Let the mass of $N_2$ be, 'x' gram and the mass of $He$ will be, '2x' gram.

Molar mass of He = 4 g/mol

Molar mass of $N_2$ = 28 g/mol

Now we have to calculate the moles of $He$ and $N_2$.

$\text{ Moles of }He=\frac{\text{ Mass of }He}{\text{ Molar mass of }He}=\frac{2xg}{4g/mole}=\frac{2x}{4}moles$

and,

$\text{ Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molar mass of }N_2}=\frac{xg}{28g/mole}=\frac{x}{28}moles$

Now we have to calculate the mass ratio of $He$ and $N_2$.

$\frac{\text{Mass of }He}{\text{Mass of }N_2}=\frac{(\frac{2x}{4}moles)}{(\frac{x}{28}moles)}=\frac{14}{1}$

Therefore, the ratio of their moles will be, 14 : 1