if the mass ratio of NaOH and H2O in an aqueous solution is 4:25 then the molality of NaOH in the solution is
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4g is weight given of NaOH and 25g is weight given of H2O so we have definition of molality
no. of moles of solute/amt of solvent (in gram)
so, 4/40=no. of moles
0.1×1000=100
100÷25= 4 molal
no. of moles of solute/amt of solvent (in gram)
so, 4/40=no. of moles
0.1×1000=100
100÷25= 4 molal
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