Physics, asked by megeetapradhan2894, 1 year ago

If the mass shown in figure is slightly displaced and then let go, then the system shall oscillate with a time period of(a) 2\pi\sqrt{\frac{m}{3k}}(b) 2\pi\sqrt{\frac{3m}{2k}}(c) 2\pi\sqrt{\frac{2m}{3k}}(d) 2\pi\sqrt{\frac{3k}{m}}

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Answered by aayushg1713
2

Correct ans is (b)

Mark this answer as BRAINLIEST please !!!

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Answered by Anonymous
0

Answer:

b) 2π√3m/2k

Explanation:

Let mass be = m

Let time be = t

The equivalent spring constant of the given diagram -

= keq = (k+k)

= k = 2k "k

keq = 2k × k/2k+k = 2k/3

Time period of the SHM will be -

T = 2π√m/keq

Therefore, T = 2π√3m/2k

Thus, If the mass shown in figure is slightly displaced and then let go, then the system shall oscillate with a time 2π√3m/2k

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