Question

If the masses of Dhvanit and Rajesh are 42 kg and 50 kg respectively and they are 1 m away from each other, then what is the gravitational force acting between them?
(G = 6.67 × 10 ^–¹¹ Nm² kg-²)​

Answer 1

Answer:

F = 14007 ^ 10^-6

Explanation:

GIVEN :-

r = 1 m, m1 = mass of Dhvanit = 42 kg,

m2  = Mass of Rajesh = 50 kg,  G  = 6.67 × 10 ^–¹¹ Nm² kg-²

SOLUTION :-

According to Newton's Universal law of Gravitation

F = G * m1 * m2 / d²

F = 6.67 * 10 ^–¹¹ * 42 * 50 / 1²

F = 14007 ^ 10^-6

Therefore, F = 14007 ^ 10^-6