If the math term of an a.p .is 1/p and it's pth term is 1/m ,then show that it's mpth term is 1
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Given ,m th term of A.P is 1/p
1/p =a+(m-1)d --> eq(1)
p th term of A.P is 1/m
1/m=a+(p-1)d --> eq(2)
(1)-(2)
1/p = a+(m-1)d
1/m=a+(p-1)d
1/p - 1/m =( m-1)d - (p-1)d
m-p/mp=(m-p)d
1/mp=d
mp=d
From eq(1)
1/p=a+(m-1)/mp
a= m-(m-1)/mp
a=1/mp
mp th term of A.P = a+ (mp-1)d
= 1/mp+ (mp-1)mp
=1/mp+1-1/mp
=1
Hence proved that mp th term is 1 .
1/p =a+(m-1)d --> eq(1)
p th term of A.P is 1/m
1/m=a+(p-1)d --> eq(2)
(1)-(2)
1/p = a+(m-1)d
1/m=a+(p-1)d
1/p - 1/m =( m-1)d - (p-1)d
m-p/mp=(m-p)d
1/mp=d
mp=d
From eq(1)
1/p=a+(m-1)/mp
a= m-(m-1)/mp
a=1/mp
mp th term of A.P = a+ (mp-1)d
= 1/mp+ (mp-1)mp
=1/mp+1-1/mp
=1
Hence proved that mp th term is 1 .
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