If the maximum amplitude of an amoplitude modulated wave is 25 V and the minimum amplitude is 5V, the modulation index is
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Answer:
Given : Modulation index m=2/3
Using m=Am/Ac
∴ 2/3=Am/Ac⟹AC=2/3Am
Maximum amplitude =10 V
∴ AC+Am=10
OR 2/3Am+Am=10 ⟹Am=4 V
∴ AC=3/2×4=6 V
Minimum amplitude =Ac−Am=6−4=2 V
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Explanation:
If the maximum amplitude of an amoplitude modulated wave is 25 V and the minimum amplitude is 5V, the modulation index is
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