If the maximum vertical height and horizontal range of a projectile are same, the angle of porjection
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Answer:45degree
Explanation:
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maximum height =u2sin2theta/2g
range =2u2sinthetacostheta/g
2u2sintetacostheta/g =u2sin2theta/2g
- sintheta/costheta =4
- tanteta =4
- teta=tan*-1 4
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