Question

If the radius of the earth word to string by 1% its mass remaining the same the value of g on the earth surface would

Answer 1

Answer:

Explanation:

Let the mass and radius of the earth be M and R respectively.  

Acceleration due to gravity, g = GM/R^2  

When the radius, R’ = R-R/100 = 99R/100 = 0.99R  

So, the acceleration due to gravity, g’ = GM/(0.99R)^2  

or, g’ = 1.02GM/R^2  

Now, the change in acceleration due to gravity,  

=g’ – g  

=(1.02-1)GM/R^2  

= (0.02)GM/R^2  

Thus, the acceleration due to gravity increases by 2%