Question

If the mean of 4 , 8 , 9 , 11 , P and 15 is 9 . find the value of P​

Answer 1

Answer:

Hey mate here is your answer,

the value of P is 7 .

hope this helps you

mark as brainliest answer plss

Answer 2

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: SOLUTION\: \: } \mid}}}}}$

$\underline{ \mathfrak{ \: \: Given, \: \: }} \\ \\ \text{The observations are : 4 , 8 , 9 , 11 , P and 15} \\ \\ \tt{Mean \: \: of \: \: the \: \: observation, \bar{x} = 9} \\ \\ \underline{ \mathfrak{ \: \: To \: \: find :-}} \\ \\ \: \: \: \: \: \text{Value of the observation P = ?}</p><p>$

$\mathfrak{Here,} \\ \\ \text{No. of total observation , n = 6} \\ \\ \tt{Sum \: \: of \: \: total \: \: observation, \sum \: x= 47 + P}$

$\underline{ \mathfrak{ \: \: We know that, \: \: }} \\ \\ \boxed{ \bold{Mean = \frac{Sum \: \: of \: \: total \: \: observation}{No. \: \: of \: \: total \: \: observation} }} \\ \\ \underline{ \bold{ \: Or, \: }} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bold{ \bar{ \: x \: } \: = \frac{ \sum \: x}{n} }}$

$\underline{ \bold{ \: \: A.T.Q., \: \: }} \\ \\ \: \: \: \: \: \: \: \: \: \: \tt{ \bar{ \: x \: } \: = \frac{ \sum \: x}{n} } \\ \tt{ \implies \: 9 = \frac{47 +P }{6} } \\ \\ \tt{ \implies \: 47 + P = 54} \\ \\ \tt{ \implies \: P = 54 - 47} \\ \\ \: \: \: \: \: \: \: \tt{ \therefore \: \: P = 7 \: }$

$\therefore \: \: \text{Value of the observation \red{ P = 7}}$

$\huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \: \: VERIFICATION\: \: } \mid}}}}}$

$\text{No. of total observation , n = 6} \\ \\ \text{Sum \: \: of \: \: total \: \: observation, } \\ \\ \tt{\sum \: x= 47 + P} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \tt{ = 47 + 7} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \tt{ = 54} \\ \\ \tt{ \therefore \: \: \bar{x} = \frac{ \sum \: x}{n} } \\ \\ \: \: \: \: \: \: \: \: \: \: \tt{ = \frac{54}{6} } \\ \\ \: \: \: \: \: \: \: \: \: \: \tt{ = 9} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \bold{ \: \: Verified. \: \: }}$