if the mean of first natural
nos is 15 them
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The first n natural numbers are 1,2,3,...,n
Given that mean of n natural numbers is 15
⟹
n
1+2+3+...+n
=15 ———(1)
We know that sum of first n natural numbers is
2
n(n+1)
⟹1+2+3+...+n=
2
n(n+1)
———(2)
Substituting (2) in (1) we get
⟹
2n
n(n+1)
=15
⟹n+1=30⟹n=30−1=29
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