Question

If the mean of 'p' and1/p is "M" then the mean of p cube and 1/p cube is
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Answer 1

$mean \: of \: p \: and \: \frac{1}{p } \: is \: M.$

$Now, \: mean \: of \: p³ \: and \: \frac{1}{ {p}^{3} } :$

(p³ + 1/p³)/2 =

[(p + 1/p)³ - 3p.1/p(p+1/p)]/2

= {(2M)³ - 3(2M)}/2

= 8M³ - 6M/2 = 4M³ - 3M