Question

If the measure of one of the equal sides of an isosceles triangle is ‘a’ unit and the third side is ‘2b’ units, then the area of the triangle by Heron’s formula is?

Answer 1

Step-by-step explanation:

$x = \frac{a + a + 2b}{2}$

$x = \frac{2(a + b)}{2}$

$x = a + b$

then

$\sqrt{x(x - a)(x - b)(x - a)}$

$\sqrt{(a + b) \times {b}^{2} \times a }$

$\sqrt{(ab) {}^{2} + {b}^{2} \times ba }$

$\sqrt{(ab) {}^{2} } + \sqrt{ {b}^{2} } \times \sqrt{ba}$

$ab + b \sqrt{ba}$

$b(a + 1) \sqrt{ba}$