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If the measures of the angles of a triangle are 2xdegree (3x-5) (4x-13 degree) then the value of X degree is​

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If the measures of the angles of a triangle are 2xdegree (3x-5) (4x-13 degree) then the value of X degree is

\sf{\pink{Solution}}

Given, ABC is a triangle

In which,

∠A=2x°

∠B=(3x-5)°

∠C=(4x-13)°

we need to find the value of x

we know that, sum of all angle in a triangle is 180°

→2x+(3x-5)+(4x-13)=180°( ∠ sum property)

→2x+3x-5+4x-13=180°

→9x-18=180°

→9x=180+18

→9x=198

→x=198/9

⁣ x=22°

\sf{HENCE,}

  • ∠A=2×22=44°
  • ∠B=3×33-5=61°
  • ∠C=4×22-13=75°

\tt{VERIFICATION}

  • (2×22)+(3×22-5)+(4×22-13)=180
  • 44+61+75=180
  • 180°=180°
  • LHS=RHS

⁣     Therefore, the value of all angle in the triangle are 44°,61°and 75°.

[tex][/tex]

⁣           

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