Math, asked by 9706100313, 1 year ago

If the median of 46,64,88,40,x,76,35,91,56,32 and 91 is 58,find the value of x. In details!

Answers

Answered by warokiarajpbtd3a
1

46 + 64 + 88 + 40 + 76 + 35 + 91 + 56  + 91 + x = 587 + x = sum  \:  median of x = sum \div no  \\  = 587 + x \div 11 = 91 \\ 587 + x = 91 \times 11 = 1001 = 587 + x \\ x = 587 - 1001 = 414
Answered by Gokusparx
3

Hello Users.......

(46 + 64 + 88 + 40 + x + 76 + 35 + 91 + 56 + 32 + 91)/11 = 58.
(619+x)/11 = 58
x+619 = 638
x = 638 - 619
x = 19

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