Question

. If the median of the distribution is 28.5, find x and y (3)

Class interval 0—10 10—20 20—30 30—40 40—50 50—60 Total

Frequency 5 x 20 15 y 5 60

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Answer 1

Answer:

It is given that the median is 28.5. So, the median lies in the group of 30 – 40. Hence, the value of x and y is 8 and 7 respectively.

Answer 2

Answer:

Here, it is given that Median =28.5 and n=∑fi=60Cummulative frequency table for the following data is given.Here n=60⇒ 2n=30Since, median is 28.5, median class is 20−30Hence, l=20,h=10,f=20,c.f.=5+x

Here, it is given that Median =28.5 and n=∑fi=60Cummulative frequency table for the following data is given.Here n=60⇒ 2n=30Since, median is 28.5, median class is 20−30Hence, l=20,h=10,f=20,c.f.=5+xTherefore, Median =l+(

f2n −cf )h28.5=20+( 2030−5−x)10

−cf )h28.5=20+( 2030−5−x)10⇒28.5=20+

−cf )h28.5=20+( 2030−5−x)10⇒28.5=20+ 225−x

⇒8.5×2=25−x

⇒8.5×2=25−x⇒x=8

⇒8.5×2=25−x⇒x=8Also, 45+x+y=60

⇒8.5×2=25−x⇒x=8Also, 45+x+y=60⇒y=60−45−x=15−8=7.

Step-by-step explanation:

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