if the mid point of line segment joining the points p(6,b-2) and Q(-2,4) is (2,-3) fimd the value of b
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Since the three points lie on the same line and two points are known, we can use their gradient to get the unknown. The gradient is the same.
Using points (-2,4)and(2,-3)
We get the gradient as :
(2,-3)-(-2,4)=cbange in your /change in x=-7/4
Getting the gradient using the point with unknown and one known point we get:
(2,-3)-(6,b-2)=change in y/change in x=(-1-b)/-4=-7/4=(1+b)/4=-7/4
4+4b=-28
4b=-32
b=-8
Using points (-2,4)and(2,-3)
We get the gradient as :
(2,-3)-(-2,4)=cbange in your /change in x=-7/4
Getting the gradient using the point with unknown and one known point we get:
(2,-3)-(6,b-2)=change in y/change in x=(-1-b)/-4=-7/4=(1+b)/4=-7/4
4+4b=-28
4b=-32
b=-8
Answered by
11
Answer:
-8
Step-by-step explanation:
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