Question

If the mid value of a class is 110 and class length is 30, then find the upper limit of the class.​

Answer 1

Answer:

⇒ Let upper limit and lower limit be x and y

⇒

2

x+y

=42 [ Given ]

∴ x+y=84 ------ ( 1 )

Now, according to the question,

⇒ x−y=10 ------ ( 2 )

Adding equation ( 1 ) and ( 2 ) we get,

2x=94

∴ x=47

And 47−y=10

∴ y=37

∴ Required class interval =37−47