Question

If the mid-value of a class is 25 and class length is 10, then boundary points of that class are 20-30.
O True
O False​

Answer 1

Question

If the mid-value of a class is 25 and class length is 10, then boundary points of that class are 20-30.

• True
• False

Solution

Let Lower Limit be L

∴ Upper Limit =L+10 [ Since, Class Width =10]

Now, we know that

ClassMark=(LowerLimit+UpperLimit)÷2

∴ (L+L+10)÷2=25 [Class Mark 25 given]

⇒ 2L+10=50

⇒ 2L=40

⇒ L=20

• Lower Limit of the class =20

• Upper Limit of the class =20+10=30

The required class is 20−30

True

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Answer 2

Answer:

true

Step-by-step explanation:

yes it is true because difference of 20-30 class is 10 , which is given

and we can also ses that mid valye of 20 30 is 25