Question

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Answer 1

Answer:

In the first experiment:-

Weight of copper oxide, (CuO)=1.288g

Weight of copper =1.03g

Weight of oxygen = Wt. of copper oxide − Wt. of copper =1.288−1.03=0.258g

∴

Wt. of oxygen

Wt. of copper

=

0.258

1.03

≈

1

4

In the second expriment:-

Weight of copper oxide (CuO)=3.672g

Weight of copper =2.938g

Weight of oxygen = Wt. of copper oxide − Wt. of copper =3.672−2.938=0.734g

∴

Wt. of oxygen

Wt. of copper

=

0.734

2.938

≈

1

4

The proportion of elements of copper and oxygen in the reactions is same.

Hence law of constant proportion is proved