If the midvalue of a class is 20 and the width of the class is 5, find the lower and upper limits of the class.
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Question:
If the midvalue of a class is 20 and the width of the class is 5, find the lower and upper limits of the class.
Solution:
Let the upper and lower limits are x and y respectively.
Now, (x + y)/2 = 20
=> x + y = 20 × 2
=> x + y = 40.....................eq.1
Again given,
class size = 5
=> x - y = 5 ........................eq.2
Add equation 1 and 2, we get
2x = 45
=> x = 45/2
=> x = 22.5
From equation 2
22.5 - y = 5
=> y = 22.5 - 5
=> y = 17.5
Answer:
So, lower limit = 17.5
So, lower limit = 17.5and upper limit = 22.5
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