If the molal elevation constant of solvent is 0.5 kg per mol ,then what will be the elevation in boilling point for 0.1 m solution?
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Explanation:
Given If the molal elevation constant of solvent is 0.5 kg per mol ,then what will be the elevation in boiling point for 0.1 m solution?
- We know that molal elevation constant is given by
- So ΔTb = Kb x m where the elevation in boiling point is ΔTb
- Molal elevation constant = Kb = 0.5 K kg / mol
- Molality of solution m = 0.1 m
- Now ΔTb = 0.5 x 0.1
- = 0.05 K
Therefore the elevation in boiling point will be 0.05 K
Reference link will be
https://brainly.in/question/14059178
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