Question

If the molality of an aquous solution of cane sugar is 0.4445 .calculate the mole fraction

Answer 1

Answer:

7.9*10^-3 mole fraction.

Explanation:

From the given question we get to know that the value of molality of the aqueous solution of cane sugar is 0.4445= mol/1 kg of water.

So, the moles of the cane sugar is 0.4445.

Since, we know that the 1 kg of wáter will have its molarity as given by 1000/18 = 55.56 mol. The molar mass of the solvent water is 18.

So, now we can find the mole fraction of the cane sugar as

0.4445/(0.4445 + 55.56) which on calculating we will get the value of mole fraction of cane sugar as 7.9*10^-3.