if the molar conductivity of 0.01M KCl Solution is 152 S cm^2 mol^-1 then then the conductivity of the solution is
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Answer:
Explanation:
Given:
Molar conductivity = 100cm²
Quantity of solution = 0.25M
Temperature = 300k
To Find:
The conductivity of the solution
Solution:
Converting the temperature = K = 0.0300 S cm−1
C = 0.25 M
Using the formula of molar conductivity -
Λm = ( k × 1000)/M
Λm =(0.0300 × 1000 )/0.25
Λm = 120 cm2 mol−1
Answer: The conductance of the solution is 120 cm² mol−1
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