Physics, asked by rahul100404, 8 months ago

If the mole fraction of solvent of binary solution is 0.95, then what is relative lowering vapour pressure of

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Answers

Answered by kunwar579
0

Explanation:

Relative lowering of vapor pressure:

The vapor pressure of a liquid is the pressure of the vapor which is in equilibrium with that liquid. The vapor pressure of a solvent is lowered when a non-volatile solute is dissolved in it to form a solution.The reduction of vapor pressure of solvent is given as

p

1

=x.p

1

0

p

1

is vapor pressure of the solution.

p

1

0

is the vapor pressure of pure solvent

x is the mole fraction of solute

Relative lowering of vapor pressure is p

1

/p

1

0

=x

Where x is mole fraction of solute and not solvent. Statement 1 is false.

Relative lowering of vapor pressure is a colligative property.

Answered by sudhakarn902
5

Answer:

0.05

Explanation:

relative lowering vapour pressure is directly proportional to mole fraction of solute

given: mole fraction of solvent = 0.95

xA+ xB= 1

xA+ 0.95= 1

xA = 1-0.95

xA = 0.05

therefore relative lowering vapour pressure= 0.05

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