Question

If the momentum of a body is doubled the kinetic energy

Answer 1

Heyamate!!

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$\mathfrak{\green{\huge{Answer}}}$

The kinetic energy of the body also get double

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$\mathcal{\red{\huge {Hope\:it\:helps}}}$

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Answer 2

${\huge{\bold{\blue{Kinetic Energy}}}}$

The formula of kinetic energy is

$E = \frac{1}{2} \times mv^2$

so it could be written as

$E = \frac{1}{2} \times mv \times v$

and mv = momentum

whose symbol is p

But, if we see practically then we will find that the mass of the body can not double suddenly the change could be only in the velocity and as the momentum is doubled it means that velocity is doubled

so now the values of $E_1$ and $E_2$ we get are

$E_1 =\frac{1}{2}mv^2$ (¡)

$E_2 = \frac{1}{2}m(2v)^2$

$E_2 = \frac{1}{2}4mv$(¡¡)

so on dividing (¡¡) from (¡)

$\frac{E_1}{E_2} = \frac{\frac{1}{2}mv^2}{\frac{1}{2}4mv}$

$\frac{E_1}{E_2} = \frac{1}{4}$

$4E_1 = E_2$

this shows that the Energy when momentum increased is four times the initial energy.