Question

if the momentum of a body is increased by 100% then the percentage increase in the kinetic energy is​

Answer 1

let initial moment be p and intial kinetic energy is k.....

than the value of k in terms of p = p^2/2m.

hence, p is increased by 100% than, new value p' becomes= p+ p×100/100.

= 2p.

than, new kinetic energy k' = 2p^2/2m.

hence, k'/k= p'/p= 2^2/1.

hence% increase= K'-K/k×100

= 4k-k/k×100

= 300% (ans)