Question

If the momentum of a body is increased by 50%, what will be the percentage increase in the kinetic energy of the body?

Answer 1

HEY MATE HERE IS YOUR ANSWER....




Let the original momentum of the body to be "p"

Increase in kinetic energy: p+(50/100)p=1.5p

Relation between momentum "p’"and kinetic energy "k" = p^2=2km(m=mass)

Therefore, k=(p^2)/2m

New kinetc energy,

k' = ((1.5p)^2)/2m (new p =1.5p)

k'=2.25*((p^2)/2m) =2.25*k

Change in k:

% increasement in KE =
(change in KE/initial KE)*100

==> (( 2.25k-k) /k ) *100

==> 125%

Increse in K.E. is by 125%