Question

If the momentum of a body is increased to x times, its kinetic energy
increases to
times.
​

Answer 1

Answer:

√x

Explanation:

k.e=p2/2m

now p=√2mk.e

as p@√k.e

so if linear momentum p raises by x times then k.e will be increased by under root times u.e √x times

Answer 2

Answer:

√K.E ∞ P

if P increased to X factor the K.E increase to √x

Explanation:

K.E = 1/2 mv²

K.E = 1/2 m²v² x 1/ m

K.E = m²v² / 2m = P² / 2m

P² = 2m K.E  ⇒ √K.E ∞ P

As P increses the K.E incresed with square root

if P increased to X factor the K.E increase to √x