if the nth term of an A.P is (2n +1) then the sum of its first three terms is??
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If nth term of an A.P is 2n+1
So, it's first term is 2(1)+1 = 3
second term is 2(2)+1 = 5
So, a = 3 and d = 5-3 = 2
Now, Sum of first three term is ,
S3 = n/2[2a+(n-1)d] = 3/2[2×3+(3-1)2]
or S3 = 3/2[6+4]
so,S3 = 15 Ans
So, it's first term is 2(1)+1 = 3
second term is 2(2)+1 = 5
So, a = 3 and d = 5-3 = 2
Now, Sum of first three term is ,
S3 = n/2[2a+(n-1)d] = 3/2[2×3+(3-1)2]
or S3 = 3/2[6+4]
so,S3 = 15 Ans
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4
Answer:
Step-by-step explanation:
If the nth terms are taken from the natural numbers then
(2(1)+1)= 3
(2(2)+1)=5
(2(3)+1)=7
Hence , ä(first term)=3 ,dif= 2,n=3
S3= 3/2 (2x3+(3-1)2)
=3/2(6+4) => 3/2(10)
= 3(5)
=> ((s3 = 15))
Hence the sum of first three terms is 15.
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