If the nth term of an A.P is tn =3n-2 find common difference
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as nth term is
tn = 3n -2
and common difference = difference of any two consecutive numbers of an ap so
the first term = 3(1) -2 = 3-2 = 1
similarly 2nd term = 3(2) -2 =6-2 =4
so common difference = 4 - 1 = 3
hope my answer helps you and please mark my answer as brainliest to help me
Answer
4.0/5
87
as nth term is
tn = 3n -2
and common difference = difference of any two consecutive numbers of an ap so
the first term = 3(1) -2 = 3-2 = 1
similarly 2nd term = 3(2) -2 =6-2 =4
so common difference = 4 - 1 = 3
hope my answer helps you and please mark my answer as brainliest to help me
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