Question

If the nth term of an arithmetic progression is (5n-2) find its first term , common difference and 25th term
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Answer 1

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Tn= (5n-2) Given

➪T1= (5× 1 - 2)= 3 and T2= (5 × 2 -2)

Thus we have

(i) first term= 3

(ii) Common difference = (T2+T1) = (8-3)

(iii)25th term = a+(25-1)d,where a = 3 and b= 5.

= (3+24×5)= 135

Step-by-step explanation:

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Answer 2

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Tn= (5n-2) Given

➪T1= (5× 1 - 2)= 3 and T2= (5 × 2 -2)

Thus we have

(i) first term= 3

(ii) Common difference = (T2+T1) = (8-3)

(iii)25th term = a+(25-1)d,where a = 3 and b= 5.

= (3+24×5)= 135