if the nth term of AP is [2n+1] find the sum of first n terms of the AP
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Here,
nth term=2n+1
so,
2n+1=a+(n-1)d
a=2n+1-(n-1)d
a=2n+1-dn+d_____eq 1
now,
Sn=n/2(2a+(n-1)d)______eq 2
putting value of a in equation 2
=n/2(2(2n+1-dn+d+dn-d)
=n/2(2n+1)
therefore,
Sn=n/2(2n+1)
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