If the nth term of na ap -1,4,9,11,... Is 129 find the value,of n
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S
n
=
2
n
{2a+(n−1)d}
S
n−1
=
2
n−1
{2a+(n−2)d}
S
n
−S
n−1
=
2
n
{2a+(n−1)d}−
2
n−1
{2a+(n−2)d}
S
n
−S
n−1
=
2
2an
+
2
n(n−1)d
−
2
2an
+
2
2a
−
2
(n−1)
(n−2)
S
n
−S
n−1
=a+(n−1)d=T
n
∴T
n
=(S
n
−S
n−1
)=(3n
2
+5n)−(3n
2
−n−2)=(6n+2).
T
m
=164⇒6m+2=164⇒6m=162⇒m=27.
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