Question

if the nth term of progression (4n-10) then the common difference ​

Answer 1

Answer:

Common difference is 4

Step-by-step explanation:

given : a(n) = 4n - 10

common difference = a(n+1) - a(n)

a(n+1) = 4(n+1) - 10 = 4n + 4 - 10 = 4n - 6

d = (4n-6) - (4n-10) = 4n - 6 - 4n + 10 = 10 - 6 = 4

Answer 2

4

explanation:

Given n

th

term of AP is 4n−10

Putting n=1,2,3,4,....., we get

At n=1:4n−10=4×1−10=4−10=−6

At n=2:4n−10=4×2−10=8−10=−2

At n=3:4n−10=4×3−10=12−10=2

At n=1:4n−10=4×4−10=16−10=6

We see that −6,−2,2,6,... are in AP as common difference is same.

Common difference =−2−(−6)=4.