If the nth terms of an Ap is 3n+7 then what is the sum of first 50 term
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n times) = 3* n(n+1)/2 + 7n = n* [3(n+1)/2 + 7] = n(3n + 17)/2. Hence, the sum of the first 40 terms will be 40 * (3*40 + 17)/2 = 40*137 / 2 = 2740. The first term of an arithmetic sequence is 5 and the 6th term is ten times the 3rd term.
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nhi aa raha bhai sorry. ......
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