Question

if the number 32a5 is divisible by 3 , then what could be the possible value of digit (A) ??
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Answer 1

Step-by-step explanation:

The sum of digits of a number divisible by 3 is a multiple of 3

3+5+a+6+4=3n

18+a=3n

If n=6⇒3n=18

If n=9,3n=27

If n=6,7,8,9⇒18+a=18,21,24,27

∴a=0,3,6,9

use this

Answer 2

If a number is divisible by 3, the sum of all it's digits should be divisible by 3 so..

3+2+a+5 should be divisible by 3..

=10+a should be divisible by 3. Now, the lowest number which is divisible by 3 after 10 is 12(3*4) so..

10+2=12

Thus, answer is 2...

hope it helps you