if the number of diagonals of a polygon is given give the formula to find its sides
Answers
Answered by
2
By using the formula for the number of diagonals of a polygon with n sides, you can determine how many sides a polygon has if you know the number of diagonals it has. For example, if a polygon has 54 diagonals, find how many sides it has.
Remember, the formula is:
diag = n*(n - 3)/2
Plugging in the known information, we know that diag = 54. So,
54 = n*(n - 3)/2
Then, solve for n using algebra. First multiply both sides by 2.
54*2 = 108 = n*(n - 3)
108 = n2 - 3n
Notice there is a squared term. This is a quadratic equation, so we can solve it either by factoring or using the quadratic formula. Here, we'll use factoring.
0 = n2 - 3n - 108
0 = (n - 12)(n + 9)
So, n = 12 or -9. But, since a polygon cannot have a negative number of sides, we know that this polygon must have 12 sides.
Remember, the formula is:
diag = n*(n - 3)/2
Plugging in the known information, we know that diag = 54. So,
54 = n*(n - 3)/2
Then, solve for n using algebra. First multiply both sides by 2.
54*2 = 108 = n*(n - 3)
108 = n2 - 3n
Notice there is a squared term. This is a quadratic equation, so we can solve it either by factoring or using the quadratic formula. Here, we'll use factoring.
0 = n2 - 3n - 108
0 = (n - 12)(n + 9)
So, n = 12 or -9. But, since a polygon cannot have a negative number of sides, we know that this polygon must have 12 sides.
tanay000000:
hii
Answered by
2
Hello!!
☺☺☺
Friend
☺☺☺
Here is the answer for your question
❤❤❤❤❤❤❤❤
Search Results
Featured snippet from the web
The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).
☺☺☺☺
Hope it helps!
✌✌✌✌✌✌
❤❤❤❤
Similar questions