If the number of revolutions made by electron in 1.0s in H-atom in its nth orbit is
twice of the number of revolutions made by electron in 1.0 s in the 2nd orbit of He+
ion, then ‘n’ is
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Answer:
hope you got the answer
Explanation:
n=number of revolution per second=circumferenceoforbitvelocityofe−
Vn=2.188×106×nzμn=0.529A∙×zn2
Putting z=1 and n=2
V2=2.188×106×21μ2
=0.529×4×10−10 =2.116×10−10mn =2×3.14×2.116×10−101.094×106 =0.082×1016
=8.2×1014revolution/sec
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