Question

if the number X + 3, 2 X + 1, x-7 are in AP. find the value of x​

Answer 1

Answer:

Therefore, we have

2x+1-(x+3)=x-7-(2x+1)2x+1−(x+3)=x−7−(2x+1)

Distributing the negative over the parenthesis, we get

2x+1-x-3=x-7-2x-12x+1−x−3=x−7−2x−1

Combine like terms on both sides

x-2=-x-8x−2=−x−8

Add x to both sides

2x-2=-82x−2=−8

Add 2 to both sides

2x=-62x=−6

Divide both sides by 2

x=-3x=−3

Thus, the value of x is -3.

Answer 2

Answer:

Given,

x + 3, 2x + 1, x - 7 are in AP

As per question,

(2x+1) - (x+3) = (x-7) - (2x+1)

2(2x+1) = (x-7) + (x+3)

4x+2 = x-7+x+3

4x+2 = 2x-4

2x = -6

x = -3