Question

if the number X is 3 less than the number Y and the sum of the squares of X and Y is 29 find the product of X and Y ​

Answer 1

Let one no be x and other be x-3

x^2+(x-3) ^2=29

x^2+x^2+9-6x=29

2x^2-6x-20=0

2(x^2-3x-10) =0

x^2-5x+2x-10=0

x(x-5) +2(x-5) =0

x=(-2), 5......

Therefore if we take one no as (-2)... then other no is(-5)

if we take x= 5 then other no = 2