Question

if the numbers 2n-1,3n+2,and 6n-1 are in A.P.,find n and hence find the number.

Answer 1

3n+2-(2n-1) =6n-1-(3n-2)
3n+2-2n+1 = 6n-1-3n-2
n+3 = 3n -3
6 = 2n
n=3

Answer 2

Answer:

Step-by-step explanation:

d=d

(3n+2) - (2n-1) = (6n-1)-(3n+2)

3n+2-2n+1 = 6n-1-3n-2

n+3=3n-3

6=2n

3=n

*GOD BLESS*