Question

If the numbers (3x-1), (2x+5) and (4x+2) are in AP , then find the value of x.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given :-

The numbers (3x-1) , (2x+5) and (4x+2) are in AP

To find :-

Find the value of x ?

Solution:-

Given numbers are :(3x-1) , (2x+5) and (4x+2)

They are in the AP

So Common difference is same.

=> (2x+5)-(3x-1) = (4x+2)-(2x+5)

=> 2x+5-3x+1 = 4x+2-2x-5

=> 6-x = 2x-3

=> -x-2x = -3-6

=> -3x = -9

=> 3x = 9

=> x = 9/3

=> x = 3

Alternative method:-

If a , b , c are in the AP then b = (a+c)/2

We have ,

a = 3x-1

b = 2x+5

c = 4x+2

so,

2x+5 = (3x-1+4x+2)/2

=> 2x+5 = (7x+1)/2

=> 2(2x+5) = 7x+1

=> 4x+10 = 7x+1

=> 10-1 = 7x-4x

=> 9 = 3x

=> 9/3 = x

=> x = 3

Therefore, x = 3

Answer:-

The value of x for the given problem is 3

Used formulae:-

If a , b , c are in the AP then b = (a+c)/2