Question

if the numerator and denominator of the fraction 3/4 be increased by the certain number and those of the fraction 5/6 be decreased by the same number the results wipl be the same find the number​

Answer 1

answer is 2/48

Step-by-step explanation:

let the no. be x and make equation according to question and answer will come

Answer 2

Answer:

The answer is 1.

Step-by-step explanation:

let the required number be 'x'

first case when the numerator and denominator of the fraction 3/4

increased by x

then the fraction formed

=(3+x)/(4+x)

second case when the numerator and denominator of the fraction 5/6 is decreased by x

then,the fraction formed

=(5-x)/(6-x)

according to question, first case and second case are same. so now

(3+x)/(4+x)=(5-x)/(6-x)

(6-x) (3 + x) = (4+x)(5-x)

18 + 6 x 3 x - x^2 = 20 - 4x + 5x - x^2

18 + 3 x 20 + x - x^2 + x^2

18+ 3 x 20 + x

3 x-x=20 - 18

(3+x)/(4+x)=(5-x)/(6-x)

(6-x) (3 + x) = (4+x) (5-x)

18+ 6 x 3 x - x^2 = 20 - 4x + 5x - x^2

18+ 3 x 20 + x - x^2 + x^2

18+ 3 x 20 + x

3 x-x=20 - 18

2x = 2

x = 1

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