If the numerator of a fraction is increased by 2 and the denominator is increased by 1, the fraction becomes 5/8 and if the numerator of the same fraction is increased by 3 and the denominator is increased by 1 the fraction becomes 3/4 What is the original fraction?
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let fraction be x/y
x+2/y+1 = 5/8
8(x+2) = 5(y+1)
8x+16 = 5y +5
8x-5y+11=0
similarily
x+3/y+1 = 3/4
4x+12 = 3y+3
4x-3y+9=0
Solving two eqs,
we get x=3 and y=7.
so fraction is 3/7
x+2/y+1 = 5/8
8(x+2) = 5(y+1)
8x+16 = 5y +5
8x-5y+11=0
similarily
x+3/y+1 = 3/4
4x+12 = 3y+3
4x-3y+9=0
Solving two eqs,
we get x=3 and y=7.
so fraction is 3/7
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