Question

If the numerator of a fraction is increased by 20% and the denominator is decreased by 5% then the new fraction becomes 60/38. The original fraction was,

Answer 1

numerator = a

denominator = b

  a x 120/100    = 60/38

   b x 95/100

 a      =  60 x 95    =     5  

b          38 x 120           4

Answer 2

Answer:

The original fraction was $\frac{5}{4}$

Step-by-step explanation:

Let the numerator be x

Let the denominator be y

Fraction : $\frac{x}{y}$

The numerator of a fraction is increased by 20%

Numerator becomes : $x+\frac{20}{100}x=\frac{120x}{100}$

The denominator is decreased by 5%

Denominator becomes : $y-\frac{5}{100}y=\frac{95y}{100}$

Fraction:$\frac{\frac{120x}{100}}{\frac{95y}{100}}$

We are given that  the numerator of a fraction is increased by 20% and the denominator is decreased by 5% then the new fraction becomes 60/38.

So, $\frac{\frac{120x}{100}}{\frac{95y}{100}}=\frac{60}{38}$

$\frac{120x}{95y}=\frac{60}{38}$

$\frac{x}{y}=\frac{60 \times 95}{38 \times 120}$

$\frac{x}{y}=\frac{5}{4}$

Hence The original fraction was $\frac{5}{4}$ .