Math, asked by raufkhan774, 1 year ago

If the numerator of a fraction is increased by 240% and the denominator of the fraction is decreased by 50%, the resultant fraction is 2(5/6). what is the original fraction?

Answers

Answered by siddhartharao77
12

Let the numerator be x and the denominator be y.

Then the original fraction = (x/y).

Now,

Given that the numerator increased by 240% and denominator decreased by 50%.

= > (x + 240 % of x)/(y - 50% of y) .

= > (x + 240x/100)/(y - 50y/100)

= > (x + 2.4x)/(y - 0.5y).

= > 3.4x/0.5y

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Given that the resultant fraction is 2(5/6) = 17/6

= > (3.4x)/(0.5y) = (17/6)

= > (x/y) = (0.5 * 17)/(3.4 * 6)

= > (x/y) = (8.5)/(20.4)

= > (x/y) = 85/204

Cancel the common factor : 17.

= > (x/y) = 5/12

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Therefore, the original fraction = (5/12).


Hope this helps!

Answered by guptapawan3695
0

Answer:

25/34

Step-by-step explanation:

120%=====6/5

1======1(initial faction)

X×340%/Y×250%====1

34X/25Y===1

X/Y===25/34

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